Kevin Pacey wrote on Sat, Nov 11, 2017 08:21 PM UTC:
I should have noted that another extreme case, perhaps, that I had in mind is, if 2 Ns are set =3x2=6, and 2Bs = 4x2=8, then it would be the case that 2N+2P vs. 2B would be numerically equivalent. However, I myself have used value systems in variants where 2Ns+P would be equal (or approx =) to 2Bs, and I found I was a bit uncomfortable with even that conclusion. [edit: I did happen to get what H.G. was saying about the board size, at least, Nicolino, though I guess I missed his point about the difference in the 2nd bishop's value, though it's still not clear to me.].
I should have noted that another extreme case, perhaps, that I had in mind is, if 2 Ns are set =3x2=6, and 2Bs = 4x2=8, then it would be the case that 2N+2P vs. 2B would be numerically equivalent. However, I myself have used value systems in variants where 2Ns+P would be equal (or approx =) to 2Bs, and I found I was a bit uncomfortable with even that conclusion. [edit: I did happen to get what H.G. was saying about the board size, at least, Nicolino, though I guess I missed his point about the difference in the 2nd bishop's value, though it's still not clear to me.].